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Let’s denote them μ and σ2. We thus have: μ = a ⋅ E(X1) + b σ2 =a2 ⋅ Var(X1) Since we know E (X1) and Var (X1) from the data, this is actually a very simple linear system with two variables (a and b) and two equations. The unique solution is: a = σ Var(X1) b = μ – σ Var(X1) ⋅ E(X1) which we can now apply on our data: sg 508 slot